Question: What is the value of Sin(75)? Solution : We shall write \[75^0=45^0+30^0 \] And apply Sin(A+B) formula \[Sin(A+B) =Sin(A)Cos(B)+Cos(A)Sin(A)\] Therefore \[Sin(75^0) = Sin(45^0+30^0) =Sin(45^0)Cos(30^0)+Cos(45^0)Sin(30^0) \] Now we shall substitute following values into above formulas \[Sin(45^0) =1/√2 , Cos(30^0) =…
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