Problem : What is the value of 1/2df/dx+1/3df/dy+1/4df/dz ? If u=f(2x-3y,3y-4z,4z-2x) Answer : If \[u=f\left(2x-3y,3y-4z,4z-2x\right)\]Substituting P=2x-3y, Q=3y-4z, R=4z-2xThen \[\frac{\partial u}{\partial x}=\frac{\partial f}{\partial P}\frac{\partial P}{\partial x}+\frac{\partial f}{\partial Q}\frac{\partial Q}{\partial x}+\frac{\partial f}{\partial R}\frac{\partial R}{\partial x}\]\[=>\frac{\partial u}{\partial x}\ =\frac{\partial f}{\partial P}2+\frac{\partial f}{\partial Q}0+\frac{\partial…
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