solved Show that f(z) = |z|^2 is differentiable only at z=0

Question : Show that f(z) = |z|^2 is differentiable only at z=0 Solution : Given complex function f(z) = |z|^2 = z z ̅ Since z= x+iy and z ̅= x-iy, i^2=-1  f(z) =u(x,y)+iv(x,y)= x^2 + y^2 u=x^2+y^2, v=0 Therefore their partial…

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