Solved If the horizontal range of the projectile is equal to it’s gained maximum height then find it’s angle of projection

Question : : If the horizontal range of the projectile is equal to it’s gained maximum height then find it’s angle of projection Solution : We know horizontal range of projectile is \[\frac{v^2Sin\left(2\theta\right)}{g}\] and maximum height is \[\frac{\left(v\ Sin\left(\theta\right)\right)^2}{2g}\] It…

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