Question : Find the solution of ode y”-9y’+20y=0 by variation of parameters method Solution : \[y^{\prime\prime}-9y^\prime+20y=e^x\cos{\left(x\right)} \] (1) To find complementary solution of ode (1) we solve corresponding homogeneous eqn of (1) \[y^{\prime\prime}-9y^\prime+20y=0\] It’s characteristics equation is \[m^2-9m+20=0\] \[m^2-5m-4m+20=0\] \[m\left(m-5\right)-4\left(m-5\right)=0\]…
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solution of ode y”-9y’+20y=e^x cos(x) by variation of parameters method
