Question: Prove that f(z) = e^z is differentiable at any point zSolution:Given complex values functionf(z) = e^zPut z =x+iyf(z) = e^z=e^(x+iy)=e^x e^(iy)f(z) = e^z =e^x(cos y + i sin y)= e^x cos y + i e^x sin ySo Real and…
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