prove that the integral -1 to 1 of 1/(x^2) is divergent

Introduction : In this solution, we will explain what is convergence of an integral and prove that the integral -1 to 1 of 1/(x^2) is divergent. Question : prove that \[\int_{-1}^{1}\frac{dx}{x^2} \] is divergent. Solution: Let \[\int_{-1}^{1}\frac{dx}{x^2} \] \[I= \int_{-1}^{1}\frac{dx}{x^2}\]…

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