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Question : Prove that set of all non zero rational numbers is a group with respect to product.
Proof :
We shall prove that set of all non zero rational numbers Q\{0} satisfies all the axioms of a group.
- Closure axiom
Product of two rational numbers is a again a rational number
for example (1/2).(2/3)=1/3 , (-1/3).(4)= -4/3, (-1/2).(-3/2) =3/4
- Associative axiom
Product of two rational numbers is associative
for example -1.((1/2).3)= -3/2 and ((-1).(1/2)).3 =-3/2=6 that is -1.((1/2).3)= ((-1).(1/2)).3
- Existence of identity
(½).1 =1/2 , 2.(1)=2, – 4.(1) =- 4
So 1 is multiplicative identity.
- Existence of inverse
1/4 . (4) = 1, 2. (1/2) =1 , -6.(-1/6) = 1
Thus multiplicative inverse of a non zero rational number is reverse of it.
Thus (Q\{0}, .) is a group.
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