If a b c are in AP then prove that 1/bc 1/ca 1/ab are in AP

Q: If a b c are in AP then prove that 1/bc 1/ca 1/ab are in AP Proof: a,b,c are in AP \[2b=a+c  \]                      Dividing this by abc both sides \[2b/abc = a/abc+c/abc\] \[2/ac =1/bc+1/ab\] \[1/bc, 1/ca, 1/ab \] are…

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