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Q: If a b c are in AP then prove that 1/bc 1/ca 1/ab are in APProof:a,b,c are in AP\[2b=a+c \] Dividing this by abc both sides\[2b/abc = a/abc+c/abc\] \[2/ac =1/bc+1/ab\]\[1/bc, 1/ca, 1/ab \] are in AP Thus if a b…
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