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Question : how to prove Pythagorean Identities?
Solution :
There are three Pythagorean Identities
- sin²𝜃 + cos²𝜃 = 1
- 1+ tan²𝜃 = sec²𝜃
- 1+ cot²𝜃 = csc² 𝜃
Proof :
Let a right triangle on the XY plane is constructed as follows

- To prove sin²𝜃 + cos²𝜃 = 1
Coordinates of A are (x,0) and B are (0,y)
So the distance AB is r=√(x^2+y^2)
Therefore r^2 = x^2+y^2
In the triangle AOB
sin 𝜃 = y/r , cos 𝜃 = x/r
Squaring and adding these sin²𝜃 + cos²𝜃 =(x^2+y^2)/r^2 =r^2/r^2 =1
Therefore sin²𝜃 + cos²𝜃 = 1
Tp prove 1+ tan²𝜃 = sec²𝜃
Divide sin²𝜃 + cos²𝜃 = 1 by cos²𝜃
tan²𝜃 +1= 1/cos²𝜃 = sec²𝜃
hence 1+ tan²𝜃 = sec²𝜃
- To prove 1+ cot²𝜃 = csc² 𝜃
Divide sin²𝜃 + cos²𝜃 = 1 by sin²𝜃
1+cot²𝜃 = 1/sin²𝜃 = cosec²𝜃
hence 1+ cot²𝜃 = csc² 𝜃
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