regula falsi algorithm in matlab to find the solution of x-3cos x=0 Solution: (a) Given function \[f\left(x\right)=x-3\cos{x}\] Clearly f(x) is a continuous function in the interval (1,2) and \[f\left(1\right)=1-2\cos{1}=-0.621<0, f\left(2\right)=2-3\cos{2}=3.248>0\] by the intermediate theorem, there must be at least one…
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