Question : Find the initial value of the transfer function \[F\left(s\right)=\frac{8}{s\left(s^2+2s+1\right)} \]Solution : We shall Use initial value theorem to find initial value f(0) of the transfer function \[F\left(s\right)=\frac{8}{s\left(s^2+2s+1\right)}\] By initial value theorem \[f\left(0\right)=limit_{s\rightarrow\infty\ }sF\left(s\right)\] \[f\left(0\right)=limit_{s\rightarrow\infty\ }\frac{8}{\left(s^2+2s+1\right)}\] We get \[f\left(0\right)=limit_{s\rightarrow\infty\…
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