Question : Find sinh(x+iy) formula Solution : Let the complex number as \[z=sinh\left(x+iy\right)\] We know that \[\sin{\left(iz\right)}=isinh\left(z\right)\] So we shall multiply and divide by i we get \[z=\frac{isinh\left(x+iy\right)}{i}=\frac{\sin{\left(i\left(x+iy\right)\right)}}{i}=\frac{\sin{\left(ix-y\right)}}{i}\] Now we shall use formula of sin(A-B) =sin(A)cos(b) -cos(A) sin(B) \[z=\frac{\sin{\left(ix-y\right)}}{i}=\frac{\sin{\left(ix\right)}\cos{\left(y\right)}-\cos{\left(ix\right)}\sin{\left(y\right)}}{i}\] Now…
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