how to find singularities of cot z

Question : how to find singularities of cot z. Solution : Singularities of cot z Since we can write \[cot\ z\ =\frac{\cos{z}}{\sin{z}}=\frac{p\left(z\right)}{q\left(z\right)}\] Singularities of cot z are the zeros of sin z \[\sin{z}=0 \] \[\sin{z}=\sin{n\pi},\ n=0,\pm1,\pm2,\pm3,\pm4,\pm5,\ldots.. \] Thus singularities of…

This Question has been answered. 

Please Subscribe to See Answer or To Get Homework Help