how do you Solve y′′ + y = sec x by variation of parameters

Question : Solve y′′ + y = sec x by variation of parameters.Solution :\[y^{\prime\prime}+y=\sec{\left(x\right)} \] (1) To find complementary solution of ode (1) we solve corresponding homogeneous eqn of (1) \[y^{\prime\prime}+y=0\] It’s characteristics equation is \[m^2+1=0\] \[m^2-i^2=0\] Since i^2=-1\[\left(m-i\right)\left(m+i\right)=0\] m=i,…

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