Question : z transform homework Solution : We know that Z-transform a causal sequence is given as \[Z\left(a^n\right)=\frac{z}{z-a},\ \left|z\right|>\left|a\right|\] (a) Therfore Z-transform of sequence \[y_n=3^n\] Using a =3 \[Z\left(3^n\right)=\frac{z}{z-3}\ ,\ \left|z\right|>3\] (b) \[y_n=\left(-1\right)^n\] Putting a =-1 in the causal sequence…
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