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Question : Does the equation 3x^2+3y^2+5x-6y+1=0 represent a circle ? If yes finds it’s radius and center.Answer : Given equation \[3x^2+3y^2+5x-6y+1=0\]Step 1 : Convert this equation into the standard equation of the circle that is \[x^2+y^2+2gx+2fy+c=0\]divide by 3 both sides\[x^2+y^2+\frac{5}{3}x-2y+\frac{1}{3}=0\]…
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