how do we find sum of an arithmetic progression?

Question : how do we find sum of an arithmetic progression?Solution :n terms of an arithmetic progression is a sequence of the form a, a+d, a+2d, a+3d, a+4d,…….a+(n-1)dIt’s sum is \[S_n = a+a+d+a+2d+a+3d+ a+4d+……+a+(n-1)d \]\[S_n = na+d+2d+3d+4d+…..+(n-1)d\] \[S_n = na+(1+2+3+4+…..+(n-1))d\]…

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